What is the solution for -6x^2y+y^'=-10x^2 ?

The solution for -6x^2y+y^'=-10x^2 is y=(e^{2x^3+c_{1}})/3+5/3

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-6x^2y+y^'=-10x^2

- 6 x^{2} y + y^{^{'}} = - 10 x^{2}

y = \frac{e ^{2 x^{3} + c_{1}}}{3} + \frac{5}{3}

Solution steps

- 6 x^{2} y + y^{'} (x) = - 10 x^{2}

Solve separable ODE:

y = \frac{e ^{2 x^{3} + c_{1}}}{3} + \frac{5}{3}

y = \frac{e ^{2 x^{3} + c_{1}}}{3} + \frac{5}{3}

\frac{1}{s ( s ^{2} + 2 s + 2 )}

\frac{5}{s ^{2} - 12} - \frac{4 s}{s ^{2} + 8}

\frac{\partial}{\partial t} (s t^{2})

y = 3 x^{2} + \frac{8 x}{3} - 2

\int \frac{900}{( 2 x - 5 ) ^{2}} d x

What is the solution for -6x^2y+y^'=-10x^2 ?
The solution for -6x^2y+y^'=-10x^2 is y=(e^{2x^3+c_{1}})/3+5/3