What is the derivative of y=3x^2+(8x)/3-2 ?

The derivative of y=3x^2+(8x)/3-2 is 6x+8/3

What is the first derivative of y=3x^2+(8x)/3-2 ?

The first derivative of y=3x^2+(8x)/3-2 is 6x+8/3

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derivative of

y = 3 x^{2} + \frac{8 x}{3} - 2

6 x + \frac{8}{3}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{8 x}{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{8 x}{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{8 x}{3}) = \frac{8}{3}

\frac{d}{d x} (2) = 0

= 6 x + \frac{8}{3} - 0

Simplify

= 6 x + \frac{8}{3}

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What is the derivative of y=3x^2+(8x)/3-2 ?
The derivative of y=3x^2+(8x)/3-2 is 6x+8/3
What is the first derivative of y=3x^2+(8x)/3-2 ?
The first derivative of y=3x^2+(8x)/3-2 is 6x+8/3