What is the integral of (8x^3-9x^2+4) ?

The integral of (8x^3-9x^2+4) is 2x^4-3x^3+4x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (8x^3-9x^2+4)

\int (8 x^{3} - 9 x^{2} + 4) d x

2 x^{4} - 3 x^{3} + 4 x + C

Solution steps

\int 8 x^{3} - 9 x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{3} d x - \int 9 x^{2} d x + \int 4 d x

\int 8 x^{3} d x = 2 x^{4}

\int 9 x^{2} d x = 3 x^{3}

\int 4 d x = 4 x

= 2 x^{4} - 3 x^{3} + 4 x

Add a constant to the solution

= 2 x^{4} - 3 x^{3} + 4 x + C

5 x - 1

\int \frac{( 1 - 2 x )}{x} d x

y = x^{3}, y = 1, x = 2

n = 0 \sum \infty \frac{3 ^{n}}{4 ^{n}}

n = 1 \sum \infty \frac{2 n + 1}{n ^{4}}

What is the integral of (8x^3-9x^2+4) ?
The integral of (8x^3-9x^2+4) is 2x^4-3x^3+4x+C