en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^3,y=1,x=2

Solution

area

y = x^{3}, y = 1, x = 2

Solution

\frac{11}{4}

+1

Decimal Notation

2.75

Solution steps

Apply the area formula:

\int_{1}^{2} x^{3} - 1 d x

Solve

\int_{1}^{2} x^{3} - 1 d x : \frac{11}{4}

The area is:

= \frac{11}{4}

Popular Examples

sum from n=0 to infinity of (3^n)/(4^n)

n = 0 \sum \infty \frac{3 ^{n}}{4 ^{n}}

sum from n=1 to infinity of (2n+1)/(n^4)

n = 1 \sum \infty \frac{2 n + 1}{n ^{4}}

integral from 1 to infinity of (1/(x^2))

\int_{1}^{\infty} (\frac{1}{x ^{2}}) d x

limit as x approaches infinity of f(x)(x)^2

x \to \infty lim (f (x) (x)^{2})

limit as x approaches-infinity of x^2-1

x \to - \infty lim (x^{2} - 1)

Frequently Asked Questions (FAQ)

What is area y=x^3,y=1,x=2 ?
The answer to area y=x^3,y=1,x=2 is 11/4