What is (\partial)/(\partial y)(xy-y^2) ?

The answer to (\partial)/(\partial y)(xy-y^2) is x-2y

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(\partial)/(\partial y)(xy-y^2)

\frac{\partial}{\partial y} (x y - y^{2})

x - 2 y

Solution steps

\frac{\partial}{\partial y} (x y - y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) - \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (y^{2}) = 2 y

= x - 2 y

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{7 + 6 x})

\int sin (5 x) cos^{\frac{4}{3}} (5 x) d x

\frac{\partial}{\partial x} (e^{x} x y)

\frac{d y}{d x} = \frac{x y + 7 x - y - 7}{x y - 2 x + 8 y - 16}

\frac{\partial}{\partial x} (3 x^{2} y^{2} + 3)

What is (\partial)/(\partial y)(xy-y^2) ?
The answer to (\partial)/(\partial y)(xy-y^2) is x-2y