What is the solution for x^{''}-3x^'-10x=20t ?

The solution for x^{''}-3x^'-10x=20t is x=c_{1}e^{5t}+c_{2}e^{-2t}-2t+3/5

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x^{''}-3x^'-10x=20t

x^{^{''}} - 3 x^{^{'}} - 10 x = 20 t

x = c_{1} e^{5 t} + c_{2} e^{- 2 t} - 2 t + \frac{3}{5}

Solution steps

x^{''} (t) - 3 x^{'} (t) - 10 x = 20 t

Solve linear ODE:

x = c_{1} e^{5 t} + c_{2} e^{- 2 t} - 2 t + \frac{3}{5}

x = c_{1} e^{5 t} + c_{2} e^{- 2 t} - 2 t + \frac{3}{5}

\int_{1}^{\infty} x^{- \frac{1}{9}} d x

\frac{2}{s ( s + 2 ) + 2}

y = \frac{23}{5} x - 12

\frac{d}{d x} (- 5 e^{- 5 x})

What is the solution for x^{''}-3x^'-10x=20t ?
The solution for x^{''}-3x^'-10x=20t is x=c_{1}e^{5t}+c_{2}e^{-2t}-2t+3/5