What is (\partial)/(\partial x)(6e^xcos(yz)) ?

The answer to (\partial)/(\partial x)(6e^xcos(yz)) is 6cos(yz)e^x

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(\partial)/(\partial x)(6e^xcos(yz))

\frac{\partial}{\partial x} (6 e^{x} cos (yz))

6 cos (yz) e^{x}

Solution steps

\frac{\partial}{\partial x} (6 e^{x} cos (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 cos (yz) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 6 cos (yz) e^{x}

\frac{d}{d x} (5 + sin (45))

x \to 0 + lim (\frac{x ^{2}}{5} - \frac{7}{x})

x \to 0 lim (2 + \frac{5}{x ^{2}})

y = (\frac{8 x ^{2}}{2 - x})^{3}

What is (\partial)/(\partial x)(6e^xcos(yz)) ?
The answer to (\partial)/(\partial x)(6e^xcos(yz)) is 6cos(yz)e^x