What is the limit as x approaches 0 of 2+5/(x^2) ?

The limit as x approaches 0 of 2+5/(x^2) is infinity

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limit as x approaches 0 of 2+5/(x^2)

x \to 0 lim (2 + \frac{5}{x ^{2}})

\infty

Solution steps

x \to 0 lim (2 + \frac{5}{x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (2 + \frac{5}{x ^{2}}) = \infty

x \to 0 + lim (2 + \frac{5}{x ^{2}}) = \infty

= \infty

y = (\frac{8 x ^{2}}{2 - x})^{3}

cos (x), sin (x), [0, \frac{π}{2}]

\int x^{5} 9 x^{2} - 1 d x

\frac{\partial}{\partial y} (3 x^{2} y + cos (y))

t y^{^{'}} + y t = 1 - y

What is the limit as x approaches 0 of 2+5/(x^2) ?
The limit as x approaches 0 of 2+5/(x^2) is infinity