What is the derivative of f(1)=(x^3+2x+8)^3 ?

The derivative of f(1)=(x^3+2x+8)^3 is 3(x^3+2x+8)^2(3x^2+2)

What is the first derivative of f(1)=(x^3+2x+8)^3 ?

The first derivative of f(1)=(x^3+2x+8)^3 is 3(x^3+2x+8)^2(3x^2+2)

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derivative of

f (1) = (x^{3} + 2 x + 8)^{3}

3 (x^{3} + 2 x + 8)^{2} (3 x^{2} + 2)

Solution steps

\frac{d}{d x} ((x^{3} + 2 x + 8)^{3})

Apply the chain rule:

3 (x^{3} + 2 x + 8)^{2} \frac{d}{d x} (x^{3} + 2 x + 8)

= 3 (x^{3} + 2 x + 8)^{2} \frac{d}{d x} (x^{3} + 2 x + 8)

\frac{d}{d x} (x^{3} + 2 x + 8) = 3 x^{2} + 2

= 3 (x^{3} + 2 x + 8)^{2} (3 x^{2} + 2)

\frac{x ^{2}}{x - 3}

\int ln (x - 20) d x

1 + t

x \to 0 + lim (x^{2 \cdot x})

\int_{1}^{\infty} \frac{1}{x + x x} d x

What is the derivative of f(1)=(x^3+2x+8)^3 ?
The derivative of f(1)=(x^3+2x+8)^3 is 3(x^3+2x+8)^2(3x^2+2)
What is the first derivative of f(1)=(x^3+2x+8)^3 ?
The first derivative of f(1)=(x^3+2x+8)^3 is 3(x^3+2x+8)^2(3x^2+2)