What is the derivative of (e^x+1)^2 ?

The derivative of (e^x+1)^2 is 2(e^x+1)e^x

What is the first derivative of (e^x+1)^2 ?

The first derivative of (e^x+1)^2 is 2(e^x+1)e^x

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derivative of

(e^{x} + 1)^{2}

2 (e^{x} + 1) e^{x}

Solution steps

\frac{d}{d x} ((e^{x} + 1)^{2})

Apply the chain rule:

2 (e^{x} + 1) \frac{d}{d x} (e^{x} + 1)

= 2 (e^{x} + 1) \frac{d}{d x} (e^{x} + 1)

\frac{d}{d x} (e^{x} + 1) = e^{x}

= 2 (e^{x} + 1) e^{x}

x \to 0 lim (\frac{x ^{2} + 3}{x ^{4}})

\int_{0}^{1} 5 cos (x^{2}) d x

x \to 0 lim (\frac{( 6 ^{x} - 8 ^{x} )}{x})

\int cos (t) + sin (t) d t

n = 1 \sum \infty \frac{1}{ln ( 3 n )}

What is the derivative of (e^x+1)^2 ?
The derivative of (e^x+1)^2 is 2(e^x+1)e^x
What is the first derivative of (e^x+1)^2 ?
The first derivative of (e^x+1)^2 is 2(e^x+1)e^x