What is the integral of cos(t)+sin(t) ?

The integral of cos(t)+sin(t) is sin(t)-cos(t)+C

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integral of cos(t)+sin(t)

\int cos (t) + sin (t) d t

sin (t) - cos (t) + C

Solution steps

\int cos (t) + sin (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (t) d t + \int sin (t) d t

\int cos (t) d t = sin (t)

\int sin (t) d t = - cos (t)

= sin (t) - cos (t)

Add a constant to the solution

= sin (t) - cos (t) + C

n = 1 \sum \infty \frac{1}{ln ( 3 n )}

\frac{( s + 1 ) ^{2}}{( s + 2 ) ^{4}}

y = \frac{3}{x}, (4, \frac{3}{4})

\int \frac{( 2 x + 1 )}{x - 1} d x

y^{^{''}} + 3 y^{^{'}} - 18 y = 0

What is the integral of cos(t)+sin(t) ?
The integral of cos(t)+sin(t) is sin(t)-cos(t)+C