What is the sum from n=0 to infinity of 1/(9^n) ?

The sum from n=0 to infinity of 1/(9^n) is 9/8

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sum from n=0 to infinity of 1/(9^n)

n = 0 \sum \infty \frac{1}{9 ^{n}}

\frac{9}{8}

Solution steps

n = 0 \sum \infty \frac{1}{9 ^{n}}

Apply Series Geometric Test:

\frac{9}{8}

= \frac{9}{8}

x \to 0 lim (\frac{- 2 - 2 cos ( x ) + 2}{x ^{4}})

f (x) = 14 x

y = tan^{2} (8 x)

\int 42 x (x + 1)^{5} d x

\int \frac{1}{2 x ^{2} + 5} d x

What is the sum from n=0 to infinity of 1/(9^n) ?
The sum from n=0 to infinity of 1/(9^n) is 9/8