What is the solution for x^2(dy)/(dx)-2xy=3y^4 ?

The solution for x^2(dy)/(dx)-2xy=3y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}

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x^2(dy)/(dx)-2xy=3y^4

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}

Solution steps

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}

Solve Bernoulli ODE:

y = (\frac{x ^{2} + 6}{x ^{2} - 6})^{3}

\frac{d}{d x} (arcsin (3 x) + arccos (3 x))

\frac{\partial}{\partial x} (sin (θ))

\frac{d}{d x} (arccot (\frac{x}{8}))

x \to 0 lim ((1 + x)^{\frac{3}{x}})

What is the solution for x^2(dy)/(dx)-2xy=3y^4 ?
The solution for x^2(dy)/(dx)-2xy=3y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}