What is the derivative of (2z^3)/3-z ?

The derivative of (2z^3)/3-z is 2z^2-1

What is the first derivative of (2z^3)/3-z ?

The first derivative of (2z^3)/3-z is 2z^2-1

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derivative of

\frac{2 z ^{3}}{3} - z

2 z^{2} - 1

Solution steps

\frac{d}{d z} (\frac{2 z ^{3}}{3} - z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d z} (\frac{2 z ^{3}}{3}) - \frac{d z}{d z}

\frac{d}{d z} (\frac{2 z ^{3}}{3}) = 2 z^{2}

\frac{d z}{d z} = 1

= 2 z^{2} - 1

f (t) = e^{2 t s i n (2 t)}

\int_{0}^{1} x (1 - x)^{10} d x

y y^{^{'}} - 21 e^{x} = 0

n = 1 \sum \infty \frac{1}{6 ^{n}}

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} + 7 y})

What is the derivative of (2z^3)/3-z ?
The derivative of (2z^3)/3-z is 2z^2-1
What is the first derivative of (2z^3)/3-z ?
The first derivative of (2z^3)/3-z is 2z^2-1