What is the solution for yy^'-21e^x=0 ?

The solution for yy^'-21e^x=0 is y=sqrt(42e^x+c_{1)},y=-sqrt(42e^x+c_{1)}

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yy^'-21e^x=0

y y^{^{'}} - 21 e^{x} = 0

y = 42 e^{x} + c_{1}, y = - 42 e^{x} + c_{1}

Solution steps

y y^{'} (x) - 21 e^{x} = 0

Solve separable ODE:

y = 42 e^{x} + c_{1}, y = - 42 e^{x} + c_{1}

y = 42 e^{x} + c_{1}, y = - 42 e^{x} + c_{1}

n = 1 \sum \infty \frac{1}{6 ^{n}}

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} + 7 y})

(1 - t) (1 + t^{2})^{- 1}

\int_{1}^{e^{2}} \frac{1}{x} d x

(2, - 3), (4, - 2)

What is the solution for yy^'-21e^x=0 ?
The solution for yy^'-21e^x=0 is y=sqrt(42e^x+c_{1)},y=-sqrt(42e^x+c_{1)}