What is the slope ofintercept (2,-3),(4,-2) ?

The slope ofintercept (2,-3),(4,-2) is y= 1/2 x-4

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slope ofintercept (2,-3),(4,-2)

slope intercept

(2, - 3), (4, - 2)

y = \frac{1}{2} x - 4

Solution steps

Compute the slope

(2, - 3), (4, - 2) : m = \frac{1}{2}

Compute the

y

intercept:

b = - 4

Construct the line equation

y = mx + b

where

m = \frac{1}{2}

and

b = - 4

y = \frac{1}{2} x - 4

f (x) = \frac{ln ( x )}{x ^{4}}

x \to 1 - lim (2)

\frac{\partial}{\partial y} (ln (x - 9 y))

y^{^{'}} + 3 y = 9 - e^{t}

y = ∣ x - 9 ∣, y = \frac{x}{2}

What is the slope ofintercept (2,-3),(4,-2) ?
The slope ofintercept (2,-3),(4,-2) is y= 1/2 x-4