What is (\partial)/(\partial y)(ln(x-9y)) ?

The answer to (\partial)/(\partial y)(ln(x-9y)) is -9/(x-9y)

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(\partial)/(\partial y)(ln(x-9y))

\frac{\partial}{\partial y} (ln (x - 9 y))

- \frac{9}{x - 9 y}

Solution steps

\frac{\partial}{\partial y} (ln (x - 9 y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{x - 9 y} \frac{\partial}{\partial y} (x - 9 y)

= \frac{1}{x - 9 y} \frac{\partial}{\partial y} (x - 9 y)

\frac{\partial}{\partial y} (x - 9 y) = - 9

= \frac{1}{x - 9 y} (- 9)

Simplify

\frac{1}{x - 9 y} (- 9) : - \frac{9}{x - 9 y}

= - \frac{9}{x - 9 y}

y^{^{'}} + 3 y = 9 - e^{t}

y = ∣ x - 9 ∣, y = \frac{x}{2}

x^{2} cos (x)

cos (y) (\frac{d y}{d t}) + sin (y) = 0

\int_{- 3}^{x^{3}} t^{3} d t

What is (\partial)/(\partial y)(ln(x-9y)) ?
The answer to (\partial)/(\partial y)(ln(x-9y)) is -9/(x-9y)