What is laplacetransform x^2cos(x) ?

The answer to laplacetransform x^2cos(x) is -(2s(-s^2+3))/((s^2+1)^3)

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laplacetransform x^2cos(x)

laplace transform

x^{2} cos (x)

- \frac{2 s ( - s ^{2} + 3 )}{( s ^{2} + 1 ) ^{3}}

Solution steps

L {x^{2} cos (x)}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

x^{2} cos (x) : f (x) = cos (x), k = 2

= (- 1)^{2} \frac{d ^{2}}{d s ^{2}} (L {cos (x)})

L {cos (x)} : \frac{s}{s ^{2} + 1}

\frac{d ^{2}}{d s ^{2}} (\frac{s}{s ^{2} + 1}) = - \frac{2 s ( - s ^{2} + 3 )}{( s ^{2} + 1 ) ^{3}}

= (- 1)^{2} (- \frac{2 s ( - s ^{2} + 3 )}{( s ^{2} + 1 ) ^{3}})

= - \frac{2 s ( - s ^{2} + 3 )}{( s ^{2} + 1 ) ^{3}}

cos (y) (\frac{d y}{d t}) + sin (y) = 0

\int_{- 3}^{x^{3}} t^{3} d t

x \to - 2 lim (x^{2} + 9 x + 6)

\int \frac{( 5 - e ^{x} )}{e ^{2 x}} d x

f (x) = x arccos (x)

What is laplacetransform x^2cos(x) ?
The answer to laplacetransform x^2cos(x) is -(2s(-s^2+3))/((s^2+1)^3)