en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of x+2x^2sin(1/x)

Solution

\frac{d}{d x} (x + 2 x^{2} sin (\frac{1}{x}))

Solution

1 + 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

Solution steps

\frac{d}{d x} (x + 2 x^{2} sin (\frac{1}{x}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2 x^{2} sin (\frac{1}{x}))

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x^{2} sin (\frac{1}{x})) = 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

= 1 + 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

Popular Examples

derivative of y=-2x^2+4x-4 derivative of

y = - 2 x^{2} + 4 x - 4

limit as x approaches-infinity of ln(x)

x \to - \infty lim (ln (x))

derivative of f(x)=(x^2)/(5+8x)derivative of

f (x) = \frac{x ^{2}}{5 + 8 x}

y^{''}+2y^'=1+t^2+e^{-2t}

y^{^{''}} + 2 y^{^{'}} = 1 + t^{2} + e^{- 2 t}

(d^2y)/(dx^2)+4y=sin(2x)

\frac{d ^{2} y}{d x ^{2}} + 4 y = sin (2 x)

Frequently Asked Questions (FAQ)

What is the derivative of x+2x^2sin(1/x) ?
The derivative of x+2x^2sin(1/x) is 1+2(2xsin(1/x)-cos(1/x))
What is the first derivative of x+2x^2sin(1/x) ?
The first derivative of x+2x^2sin(1/x) is 1+2(2xsin(1/x)-cos(1/x))