What is the derivative of 4x-5x^{7/8} ?

The derivative of 4x-5x^{7/8} is 4-(35)/(8x^{1/8)}

What is the first derivative of 4x-5x^{7/8} ?

The first derivative of 4x-5x^{7/8} is 4-(35)/(8x^{1/8)}

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\frac{d}{d x} (4 x - 5 x^{\frac{7}{8}})

4 - \frac{35}{8 x ^{\frac{1}{8}}}

Solution steps

\frac{d}{d x} (4 x - 5 x^{\frac{7}{8}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (5 x^{\frac{7}{8}})

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5 x^{\frac{7}{8}}) = \frac{35}{8 x ^{\frac{1}{8}}}

= 4 - \frac{35}{8 x ^{\frac{1}{8}}}

f (x) = 8 e^{x} + x, (0, 8)

\int_{1}^{e^{2}} \frac{ln ^{3} ( x ^{2} )}{x} d x

n = 0 \sum \infty \frac{n !}{1 0 ^{n}}

\frac{d y}{d x} = y (8 x^{2} + 6)

\int_{e}^{\infty} \frac{ln ( x )}{x} d x

What is the derivative of 4x-5x^{7/8} ?
The derivative of 4x-5x^{7/8} is 4-(35)/(8x^{1/8)}
What is the first derivative of 4x-5x^{7/8} ?
The first derivative of 4x-5x^{7/8} is 4-(35)/(8x^{1/8)}