What is the integral of (10)/(x^2) ?

The integral of (10)/(x^2) is -(10)/x+C

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integral of (10)/(x^2)

\int \frac{10}{x ^{2}} d x

- \frac{10}{x} + C

Solution steps

\int \frac{10}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= 10 (- \frac{1}{x})

Simplify

10 (- \frac{1}{x}) : - \frac{10}{x}

= - \frac{10}{x}

Add a constant to the solution

= - \frac{10}{x} + C

\frac{\partial}{\partial x} (7 e^{x} cos (yz))

x^{4} f (x)

(\frac{d y}{d x}) - 3 y = e^{2 x}

y^{^{''}} + 4 y^{^{'}} = 6 e^{- 3 t}

\frac{d y}{d x} + \frac{9 y}{1000 + x} = 0.405