What is the derivative of y=3x^2-4 ?

The derivative of y=3x^2-4 is 6x

What is the first derivative of y=3x^2-4 ?

The first derivative of y=3x^2-4 is 6x

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derivative of

y = 3 x^{2} - 4

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= 6 x - 0

Simplify

= 6 x

\int 1 + cos (4 x) d x

5 x^{3} + 4 x

\int_{0}^{\infty} \frac{1}{x ^{2} + x} d x

\frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2} + 1})

\frac{d y}{d x} = - 0.05 y

What is the derivative of y=3x^2-4 ?
The derivative of y=3x^2-4 is 6x
What is the first derivative of y=3x^2-4 ?
The first derivative of y=3x^2-4 is 6x