What is the limit as x approaches 1 of ln(x)-5x ?

The limit as x approaches 1 of ln(x)-5x is -5

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limit as x approaches 1 of ln(x)-5x

x \to 1 lim (ln (x) - 5 x)

- 5

Solution steps

x \to 1 lim (ln (x) - 5 x)

Plug in the value

x = 1

= ln (1) - 5 \cdot 1

Simplify

ln (1) - 5 \cdot 1 : - 5

= - 5

f (b) = (4 - a - b - c) z

x \to + (- 0) lim (e^{\frac{1}{x}})

\frac{d}{d t} (5 cos (t))

\int_{0}^{1} \frac{1}{x ^{2} + 16} d x

y^{^{''}} - 5 y^{^{'}} - 2 y = 0

What is the limit as x approaches 1 of ln(x)-5x ?
The limit as x approaches 1 of ln(x)-5x is -5