What is the derivative of sqrt(y/2) ?

The derivative of sqrt(y/2) is 1/(2sqrt(2)\sqrt{y)}

What is the first derivative of sqrt(y/2) ?

The first derivative of sqrt(y/2) is 1/(2sqrt(2)\sqrt{y)}

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derivative of

\frac{y}{2}

\frac{1}{2 2 y}

Solution steps

\frac{d}{d y} (\frac{y}{2})

Apply the chain rule:

\frac{1}{2 \frac{y}{2}} \frac{d}{d y} (\frac{y}{2})

= \frac{1}{2 \frac{y}{2}} \frac{d}{d y} (\frac{y}{2})

\frac{d}{d y} (\frac{y}{2}) = \frac{1}{2}

= \frac{1}{2 \frac{y}{2}} \cdot \frac{1}{2}

Simplify

\frac{1}{2 \frac{y}{2}} \cdot \frac{1}{2} : \frac{1}{2 2 y}

= \frac{1}{2 2 y}

\frac{d}{d x} (- \frac{48 x}{( x ^{2} + 12 ) ^{2}})

\int e^{i x} d x

\frac{1}{sin ( x )}

\int sin (2 θ) sin (6 θ) d θ

2 sin (3 t) cos (3 t)

What is the derivative of sqrt(y/2) ?
The derivative of sqrt(y/2) is 1/(2sqrt(2)\sqrt{y)}
What is the first derivative of sqrt(y/2) ?
The first derivative of sqrt(y/2) is 1/(2sqrt(2)\sqrt{y)}