What is the integral of 3/(sqrt(x^5)) ?

The integral of 3/(sqrt(x^5)) is -2/(x^{3/2)}+C

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integral of 3/(sqrt(x^5))

\int \frac{3}{x ^{5}} d x

- \frac{2}{x ^{\frac{3}{2}}} + C

Solution steps

\int \frac{3}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{5}} d x

x^{5} = x^{\frac{5}{2}},

assuming

x \geq 0

= 3 \cdot \int \frac{1}{x ^{\frac{5}{2}}} d x

Apply the Power Rule

: - \frac{2}{3 x ^{\frac{3}{2}}}

= 3 (- \frac{2}{3 x ^{\frac{3}{2}}})

Simplify

3 (- \frac{2}{3 x ^{\frac{3}{2}}}) : - \frac{2}{x ^{\frac{3}{2}}}

= - \frac{2}{x ^{\frac{3}{2}}}

Add a constant to the solution

= - \frac{2}{x ^{\frac{3}{2}}} + C

\frac{\partial}{\partial x} (x^{4} \cdot y^{2} - x^{3} \cdot y)

f (x) = e^{2 x + 1}

\frac{d}{d x} (x^{3} + a x^{2} y + b x y^{2} + y^{3})

\int 3 x + 2 cos (5 x) d x

\int e^{0.5 t} d t

What is the integral of 3/(sqrt(x^5)) ?
The integral of 3/(sqrt(x^5)) is -2/(x^{3/2)}+C