What is the solution for (d^2y)/(dx^2)+2(dy)/(dx)-3y=2x-17 ?

The solution for (d^2y)/(dx^2)+2(dy)/(dx)-3y=2x-17 is y=c_{1}e^x+c_{2}e^{-3x}-(2x)/3+47/9

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(d^2y)/(dx^2)+2(dy)/(dx)-3y=2x-17

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} - 3 y = 2 x - 17

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{2 x}{3} + \frac{47}{9}

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} - 3 y = 2 x - 17

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{2 x}{3} + \frac{47}{9}

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{2 x}{3} + \frac{47}{9}

\frac{\partial}{\partial y} (x tan (y))

y = - 2 x^{2} - x + 6

\int_{0}^{a} x sin^{2} (\frac{π}{a} x) d x

\frac{\partial}{\partial x} (- 2 x y^{2})

\frac{d x}{d t} = x (1 - x)

What is the solution for (d^2y)/(dx^2)+2(dy)/(dx)-3y=2x-17 ?
The solution for (d^2y)/(dx^2)+2(dy)/(dx)-3y=2x-17 is y=c_{1}e^x+c_{2}e^{-3x}-(2x)/3+47/9