What is the derivative of 5*2^x ?

The derivative of 5*2^x is 5*2^xln(2)

What is the first derivative of 5*2^x ?

The first derivative of 5*2^x is 5*2^xln(2)

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\frac{d}{d x} (5 \cdot 2^{x})

5 \cdot 2^{x} ln (2)

Solution steps

\frac{d}{d x} (5 \cdot 2^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 5 \cdot 2^{x} ln (2)

\int_{0}^{π} 9 x sin (x) d x

\frac{\partial}{\partial x} (y \cdot e^{2 x})

\int_{1}^{4} (3 - ∣ x - 3 ∣) d x

f (x) = \frac{2 x}{x ^{2} - 7}

\frac{d}{d x} (x^{2} + (y - 1)^{2})

What is the derivative of 5*2^x ?
The derivative of 5*2^x is 5*2^xln(2)
What is the first derivative of 5*2^x ?
The first derivative of 5*2^x is 5*2^xln(2)