What is the derivative of 81cos(3x) ?

The derivative of 81cos(3x) is -243sin(3x)

What is the first derivative of 81cos(3x) ?

The first derivative of 81cos(3x) is -243sin(3x)

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\frac{d}{d x} (81 cos (3 x))

- 243 sin (3 x)

Solution steps

\frac{d}{d x} (81 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 81 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 81 (- sin (3 x) \cdot 3)

Simplify

= - 243 sin (3 x)

\frac{\partial}{\partial x} (x^{3} - 6 x^{2} - 34 x + 40)

f (x) = x (x - 3)

\frac{d}{d x} ((3 x - 1)^{4} (- 2 x + 9)^{5})

\frac{d}{d p} (\frac{400}{p ^{2}})

\int (9 x^{2} - 6 x + 5) d x

What is the derivative of 81cos(3x) ?
The derivative of 81cos(3x) is -243sin(3x)
What is the first derivative of 81cos(3x) ?
The first derivative of 81cos(3x) is -243sin(3x)