What is the derivative of 3x^2-2x+1 ?

The derivative of 3x^2-2x+1 is 6x-2

What is the first derivative of 3x^2-2x+1 ?

The first derivative of 3x^2-2x+1 is 6x-2

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\frac{d}{d x} (3 x^{2} - 2 x + 1)

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x - 2 + 0

Simplify

= 6 x - 2

y^{^{'}} cot (x) + y = 2

\frac{d}{d x} (\frac{sin ( 2 x )}{5 x ^{2}})

\int 6 x^{3} e^{- x^{2}} d x

\frac{d}{d z} (cos (z))

x \to 0 lim (π)

What is the derivative of 3x^2-2x+1 ?
The derivative of 3x^2-2x+1 is 6x-2
What is the first derivative of 3x^2-2x+1 ?
The first derivative of 3x^2-2x+1 is 6x-2