What is the solution for (dy)/(dx-y^2)=36 ?

The solution for (dy)/(dx-y^2)=36 is y=-(e^{72x+2c_{1}})/(1-e^{2(36x+c_{1))}}-1/(1-e^{2(36x+c_{1))}}

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(dy)/(dx-y^2)=36

\frac{d y}{d x - y ^{2}} = 36

y = - \frac{e ^{72 x + 2 c_{1}}}{1 - e ^{2 (36 x + c_{1})}} - \frac{1}{1 - e ^{2 (36 x + c_{1})}}

Solution steps

\frac{d y}{d x - y ^{2}} = 36

Solve separable ODE:

y = - \frac{e ^{72 x + 2 c_{1}}}{1 - e ^{2 (36 x + c_{1})}} - \frac{1}{1 - e ^{2 (36 x + c_{1})}}

y = - \frac{e ^{72 x + 2 c_{1}}}{1 - e ^{2 (36 x + c_{1})}} - \frac{1}{1 - e ^{2 (36 x + c_{1})}}

x \to 0 lim (\frac{cos ( 4 x ) - 1}{x})

\frac{\partial}{\partial y} (2 x sin (y))

v \to 4 + lim (\frac{4 - v}{∣ 4 - v ∣})

\frac{\partial}{\partial x} (x^{2} + 5)

cos^{2} (8 t)

What is the solution for (dy)/(dx-y^2)=36 ?
The solution for (dy)/(dx-y^2)=36 is y=-(e^{72x+2c_{1}})/(1-e^{2(36x+c_{1))}}-1/(1-e^{2(36x+c_{1))}}