What is the limit as x approaches 1 of 2^{1/(x-1)} ?

The limit as x approaches 1 of 2^{1/(x-1)} is diverges

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limit as x approaches 1 of 2^{1/(x-1)}

x \to 1 lim (2^{\frac{1}{x - 1}})

diverges

Solution steps

x \to 1 lim (2^{\frac{1}{x - 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (2^{\frac{1}{x - 1}}) = \infty

x \to 1 - lim (2^{\frac{1}{x - 1}}) = 0

= diverges

\int \frac{x + 6}{( x + 2 ) ^{2}} d x

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\frac{\partial}{\partial x} (3 x^{4} - 65 x^{3})

\int_{0}^{\frac{π}{6}} cos (3 x) d x

y^{^{''}} + y = cos (t), y (0) = 0, y^{^{'}} (0) = 0

What is the limit as x approaches 1 of 2^{1/(x-1)} ?
The limit as x approaches 1 of 2^{1/(x-1)} is diverges