What is the limit as x approaches 0 of 1+sqrt(x) ?

The limit as x approaches 0 of 1+sqrt(x) is 1

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limit as x approaches 0 of 1+sqrt(x)

x \to 0 lim (1 + x)

1

Solution steps

x \to 0 lim (1 + x)

Plug in the value

x = 0

= 1 + 0

Simplify

= 1

y = 8 x^{\frac{1}{2}} + 8 x^{\frac{3}{2}} + 6, at x = 4

\int \frac{2 + x}{2 - x} d x

\frac{\partial}{\partial x} (\frac{1}{2 x ^{\frac{1}{2}}})

y = 20 x

y^{^{'''}} - 2 y^{^{''}} - y + 2 y = 0

What is the limit as x approaches 0 of 1+sqrt(x) ?
The limit as x approaches 0 of 1+sqrt(x) is 1