What is the derivative of sec^2(xdx) ?

The derivative of sec^2(xdx) is d(2xsec^2(x)tan(x)+sec^2(x))

What is the first derivative of sec^2(xdx) ?

The first derivative of sec^2(xdx) is d(2xsec^2(x)tan(x)+sec^2(x))

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\frac{d}{d x} (sec^{2} (x) d x)

d (2 x sec^{2} (x) tan (x) + sec^{2} (x))

Solution steps

\frac{d}{d x} (sec^{2} (x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (sec^{2} (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec^{2} (x), g = x

= d (\frac{d}{d x} (sec^{2} (x)) x + \frac{d x}{d x} sec^{2} (x))

\frac{d}{d x} (sec^{2} (x)) = 2 sec^{2} (x) tan (x)

\frac{d x}{d x} = 1

= d (2 sec^{2} (x) tan (x) x + 1 \cdot sec^{2} (x))

Simplify

= d (2 x sec^{2} (x) tan (x) + sec^{2} (x))

(6 - 10 y + e^{- 5 x}) d x - 2 d y = 0

\frac{2 - s}{s ^{2} + 6 s + 34}

\frac{1 - x}{1 + x}

\frac{d}{d x} ((cos^{2} (x)) x)

\frac{\partial}{\partial x} (x y)

What is the derivative of sec^2(xdx) ?
The derivative of sec^2(xdx) is d(2xsec^2(x)tan(x)+sec^2(x))
What is the first derivative of sec^2(xdx) ?
The first derivative of sec^2(xdx) is d(2xsec^2(x)tan(x)+sec^2(x))