What is the derivative of ln(x^3+2x) ?

The derivative of ln(x^3+2x) is 3/x+2

What is the first derivative of ln(x^3+2x) ?

The first derivative of ln(x^3+2x) is 3/x+2

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\frac{d}{d x} (ln (x^{3}) + 2 x)

\frac{3}{x} + 2

Solution steps

\frac{d}{d x} (ln (x^{3}) + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x^{3})) + \frac{d}{d x} (2 x)

\frac{d}{d x} (ln (x^{3})) = \frac{3}{x}

\frac{d}{d x} (2 x) = 2

= \frac{3}{x} + 2

\frac{d}{d x} (cos (x) sin^{2} (x))

y^{^{'}} = - 4 x y

\frac{\partial}{\partial x} (\frac{x y}{x + 7})

\int arcsec (x) d x

3^{x}

What is the derivative of ln(x^3+2x) ?
The derivative of ln(x^3+2x) is 3/x+2
What is the first derivative of ln(x^3+2x) ?
The first derivative of ln(x^3+2x) is 3/x+2