What is the integral of arcsec(x) ?

The integral of arcsec(x) is xarcsec(x)-ln|x+sqrt(x^2-1)|+C

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integral of arcsec(x)

\int arcsec (x) d x

x arcsec (x) - ln x + x^{2} - 1 + C

Solution steps

\int arcsec (x) d x

Apply Integration By Parts

: x arcsec (x) - \int \frac{x}{x ^{2} x ^{2} - 1} d x

= x arcsec (x) - \int \frac{x}{x ^{2} x ^{2} - 1} d x

\int \frac{x}{x ^{2} x ^{2} - 1} d x = ln x + x^{2} - 1

= x arcsec (x) - ln x + x^{2} - 1

Add a constant to the solution

= x arcsec (x) - ln x + x^{2} - 1 + C

3^{x}

f (x) = sin (sin (x)), at x = 2 π, 0

f (x) = arccos (x)

\frac{d}{d x} (3 sin (x) + 2 cos (x))

\int 6 x^{6} d x

What is the integral of arcsec(x) ?
The integral of arcsec(x) is xarcsec(x)-ln|x+sqrt(x^2-1)|+C