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Popular >

y^{''}=2y^'+8y

Solution

y^{^{''}} = 2 y^{^{'}} + 8 y

Solution

y = c_{1} e^{4 t} + c_{2} e^{- 2 t}

Solution steps

y^{''} (t) = 2 y^{'} (t) + 8 y

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{- 2 t}

y = c_{1} e^{4 t} + c_{2} e^{- 2 t}

Popular Examples

integral of 4/3 e^{4x}

\int \frac{4}{3} e^{4 x} d x

derivative of (x^2+3^3)

\frac{d}{d x} ((x^{2} + 3)^{3})

(\partial)/(\partial y)(3/2 (x+1)^2(y^2-9))

\frac{\partial}{\partial y} (\frac{3}{2} (x + 1)^{2} (y^{2} - 9))

integral of x/((25+x^2)^{3/2)}

\int \frac{x}{( 25 + x ^{2} ) ^{\frac{3}{2}}} d x

derivative of g(x)=sqrt(6-7x)derivative of

g (x) = 6 - 7 x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}=2y^'+8y ?
The solution for y^{''}=2y^'+8y is y=c_{1}e^{4t}+c_{2}e^{-2t}