What is the integral from 1/2 to 5 of 8xln(2x) ?

The integral from 1/2 to 5 of 8xln(2x) is 8(-99/16+25/2 ln(10))

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integral from 1/2 to 5 of 8xln(2x)

\int_{\frac{1}{2}}^{5} 8 x ln (2 x) d x

8 (- \frac{99}{16} + \frac{25}{2} ln (10))

Decimal Notation

180.75850 \dots

Solution steps

\int_{\frac{1}{2}}^{5} 8 x ln (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{\frac{1}{2}}^{5} x ln (2 x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x]_{\frac{1}{2}}^{5}

= 8 [\frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x]_{\frac{1}{2}}^{5}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 8 [\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4}]_{\frac{1}{2}}^{5}

Compute the boundaries:

- \frac{99}{16} + \frac{25}{2} ln (10)

= 8 (- \frac{99}{16} + \frac{25}{2} ln (10))

\frac{\partial}{\partial x} (\frac{- 6 x + 1 y}{- 8 x - 1 y})

\int_{0}^{1} \frac{2}{3 x ^{2} + 4 x + 1} d x

x \to 0 lim (\frac{6 ^{x} - 4 ^{x}}{x})

\int - x^{2} \frac{3}{3} d x

\frac{d}{d x} (x tan (y))

What is the integral from 1/2 to 5 of 8xln(2x) ?
The integral from 1/2 to 5 of 8xln(2x) is 8(-99/16+25/2 ln(10))