What is the limit as x approaches 4 of x^2+sqrt(7-x) ?

The limit as x approaches 4 of x^2+sqrt(7-x) is 16+sqrt(3)

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limit as x approaches 4 of x^2+sqrt(7-x)

x \to 4 lim (x^{2} + 7 - x)

16 + 3

Decimal

17.73205 \dots

Solution steps

x \to 4 lim (x^{2} + 7 - x)

Plug in the value

x = 4

= 4^{2} + 7 - 4

Simplify

= 16 + 3

x^{2} y^{^{''}} - 16 x y^{^{'}} + 72 y = 0

\frac{d}{d x} (\frac{2 x}{x ^{2} + 1})

f (x) = 6 x - x^{2}

\int \frac{1}{5 - 5 x} d x

y^{^{'}} + y^{3} x + y = 0

What is the limit as x approaches 4 of x^2+sqrt(7-x) ?
The limit as x approaches 4 of x^2+sqrt(7-x) is 16+sqrt(3)