What is the solution for y^'+y^3x+y=0 ?

The solution for y^'+y^3x+y=0 is y=sqrt(2/(-2x-1+2c_{1)e^{2x)}},y=-sqrt(2/(-2x-1+2c_{1)e^{2x)}}

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y^'+y^3x+y=0

y^{^{'}} + y^{3} x + y = 0

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

Solution steps

y^{'} (x) + y^{3} x + y = 0

Solve Bernoulli ODE:

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

\int cos (2 u) d u

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What is the solution for y^'+y^3x+y=0 ?
The solution for y^'+y^3x+y=0 is y=sqrt(2/(-2x-1+2c_{1)e^{2x)}},y=-sqrt(2/(-2x-1+2c_{1)e^{2x)}}