What is the sum from x=1 to infinity of x/(x^2+1) ?

The sum from x=1 to infinity of x/(x^2+1) is diverges

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sum from x=1 to infinity of x/(x^2+1)

x = 1 \sum \infty \frac{x}{x ^{2} + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{n ^{2} + 1}

Apply Series Limit Comparison Test:

diverges

= diverges

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What is the sum from x=1 to infinity of x/(x^2+1) ?
The sum from x=1 to infinity of x/(x^2+1) is diverges