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Popular >

y^'+y/x =9x^3y^2

Solution

y^{^{'}} + \frac{y}{x} = 9 x^{3} y^{2}

Solution

y = \frac{1}{x ( - 3 x ^{3} + c _{1} )}

Solution steps

y^{'} (x) + \frac{y}{x} = 9 x^{3} y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 3 x ^{3} + c _{1} )}

y = \frac{1}{x ( - 3 x ^{3} + c _{1} )}

Popular Examples

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\frac{d}{d x} (n^{x})

y^{''}+6y^'+9y=0

y^{^{''}} + 6 y^{^{'}} + 9 y = 0

(dy)/(dt)-(3/t)y=2t^3e^{2t},y(1)=0

\frac{d y}{d t} - (\frac{3}{t}) y = 2 t^{3} e^{2 t}, y (1) = 0

integral of (x+5)/(x-2)

\int \frac{x + 5}{x - 2} d x

integral of 6θcos(θ)

\int 6 θ cos (θ) d θ

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x =9x^3y^2 ?
The solution for y^'+y/x =9x^3y^2 is y= 1/(x(-3x^3+c_{1))}