What is area f(x)=sin(2x),0, pi/2 ?

The answer to area f(x)=sin(2x),0, pi/2 is 1

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area f(x)=sin(2x),0, pi/2

area

f (x) = sin (2 x), 0, \frac{π}{2}

1

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ sin (2 x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ sin (2 x) ∣ d x : 1

The area is:

= 1

\frac{d}{d x} (5 sin (x) + 3 cos (x))

\frac{d}{d x} (e^{- x y})

ln (4 + x)

x \to 0 lim (x (e^{\frac{1}{x}} - 1))

\frac{d}{d x} (e^{2 s i n (x)})

What is area f(x)=sin(2x),0, pi/2 ?
The answer to area f(x)=sin(2x),0, pi/2 is 1