What is the limit as x approaches 0 of x(e^{1/x}-1) ?

The limit as x approaches 0 of x(e^{1/x}-1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of x(e^{1/x}-1)

x \to 0 lim (x (e^{\frac{1}{x}} - 1))

diverges

Solution steps

x \to 0 lim (x (e^{\frac{1}{x}} - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x (e^{\frac{1}{x}} - 1)) = \infty

x \to 0 - lim (x (e^{\frac{1}{x}} - 1)) = 0

= diverges

\frac{d}{d x} (e^{2 s i n (x)})

5 x^{2} y^{^{'}} = y^{^{'}} + 9 x e^{- y}

\int ln (x) x^{7} d x

y = - 2 x^{4} + 7 x e^{x}

\int 3 π cos^{3} (5 π x) sin^{7} (5 π x) d x

What is the limit as x approaches 0 of x(e^{1/x}-1) ?
The limit as x approaches 0 of x(e^{1/x}-1) is diverges