What is the derivative of y=-2x^4+7xe^x ?

The derivative of y=-2x^4+7xe^x is -8x^3+7(e^x+e^xx)

What is the first derivative of y=-2x^4+7xe^x ?

The first derivative of y=-2x^4+7xe^x is -8x^3+7(e^x+e^xx)

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derivative of

y = - 2 x^{4} + 7 x e^{x}

- 8 x^{3} + 7 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (- 2 x^{4} + 7 x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (7 x e^{x})

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (7 x e^{x}) = 7 (e^{x} + e^{x} x)

= - 8 x^{3} + 7 (e^{x} + e^{x} x)

\int 3 π cos^{3} (5 π x) sin^{7} (5 π x) d x

10 t^{4}

\frac{d y}{d x} - (x + 1) y = x y^{2}

7 t y^{^{'}} + y = 0, y (1) = 1

\int 5 x 2 x^{2} + 3 d x

What is the derivative of y=-2x^4+7xe^x ?
The derivative of y=-2x^4+7xe^x is -8x^3+7(e^x+e^xx)
What is the first derivative of y=-2x^4+7xe^x ?
The first derivative of y=-2x^4+7xe^x is -8x^3+7(e^x+e^xx)