What is the integral from-2 to 2 of 1/(sqrt(4-x^2)) ?

The integral from-2 to 2 of 1/(sqrt(4-x^2)) is pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 2 of 1/(sqrt(4-x^2))

\int_{- 2}^{2} \frac{1}{4 - x ^{2}} d x

π

Decimal Notation

3.14159 \dots

Solution steps

\int_{- 2}^{2} \frac{1}{4 - x ^{2}} d x

Apply Trigonometric Substitution

: \int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d u

= \int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d u

Integral of a constant:

\int a d x = a x

= [1 \cdot u]_{- \frac{π}{2}}^{\frac{π}{2}}

Simplify

= [u]_{- \frac{π}{2}}^{\frac{π}{2}}

Compute the boundaries:

π

= π

y = 6 x + \frac{10}{3}

\frac{d}{d x} (2 x^{\frac{1}{2}} y^{\frac{1}{2}})

\frac{d}{d x} (\frac{4}{cos ( x )} + \frac{1}{tan ( x )})

\frac{\partial}{\partial y} (3 x sin (x y))

y^{^{''}} + y = sin (6 t)

What is the integral from-2 to 2 of 1/(sqrt(4-x^2)) ?
The integral from-2 to 2 of 1/(sqrt(4-x^2)) is pi