What is the solution for y^{''}+y=sin(6t) ?

The solution for y^{''}+y=sin(6t) is y=c_{1}cos(t)+c_{2}sin(t)-1/35 sin(6t)

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y^{''}+y=sin(6t)

y^{^{''}} + y = sin (6 t)

y = c_{1} cos (t) + c_{2} sin (t) - \frac{1}{35} sin (6 t)

Solution steps

y^{''} (t) + y = sin (6 t)

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) - \frac{1}{35} sin (6 t)

y = c_{1} cos (t) + c_{2} sin (t) - \frac{1}{35} sin (6 t)

y = x^{4} + 2 x^{2} - x, (1, 2)

\int 16 x ln (6 x) d x

x y^{^{'}} + y = 8 x y^{2}

(4 x + 5)^{- 1}

n = 0 \sum \infty \frac{3}{4 ^{n}}

What is the solution for y^{''}+y=sin(6t) ?
The solution for y^{''}+y=sin(6t) is y=c_{1}cos(t)+c_{2}sin(t)-1/35 sin(6t)