What is area y=sin^2(pix),[0,1] ?

The answer to area y=sin^2(pix),[0,1] is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=sin^2(pix),[0,1]

area

y = sin^{2} (π x), [0, 1]

\frac{1}{2}

Solution steps

Apply the area formula:

\int_{0}^{1} ∣ sin (π x) ∣^{2} d x

Solve

\int_{0}^{1} ∣ sin (π x) ∣^{2} d x : \frac{1}{2}

The area is:

= \frac{1}{2}

\frac{d}{d x} (\frac{5}{x + 4})

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{9 + 8 x})

\int_{0}^{2} - 2 x^{2} - 4 d x

y = \frac{1}{2} x, y = \frac{6}{x}

\int \frac{t ^{3}}{1 + t} d t