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Popular >

2xy^'+y=6x,y(4)=23

Solution

2 x y^{^{'}} + y = 6 x, y (4) = 23

Solution

y = 2 x + \frac{30}{x}

Solution steps

2 x y^{'} (x) + y = 6 x

Solve linear ODE:

y = 2 x + \frac{30}{x}

y = 2 x + \frac{30}{x}

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Frequently Asked Questions (FAQ)

What is the solution for 2xy^'+y=6x,y(4)=23 ?
The solution for 2xy^'+y=6x,y(4)=23 is y=2x+(30)/(sqrt(x))