What is the derivative of f(x)=(x^2+1)^4 ?

The derivative of f(x)=(x^2+1)^4 is 8x(x^2+1)^3

What is the first derivative of f(x)=(x^2+1)^4 ?

The first derivative of f(x)=(x^2+1)^4 is 8x(x^2+1)^3

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derivative of

f (x) = (x^{2} + 1)^{4}

8 x (x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{4})

Apply the chain rule:

4 (x^{2} + 1)^{3} \frac{d}{d x} (x^{2} + 1)

= 4 (x^{2} + 1)^{3} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 4 (x^{2} + 1)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} + 1)^{3}

y^{^{'}} = 0.15 ln (\frac{2000}{y}) y

\int_{- 2}^{2} 4 x - x^{3} d x

\frac{d y}{d x} = \frac{e ^{x}}{7 + e ^{x}}

\int \frac{( 1 + sin ( 2 x ) ) ^{4}}{sec ( 2 x )} d x

3 x - 2

What is the derivative of f(x)=(x^2+1)^4 ?
The derivative of f(x)=(x^2+1)^4 is 8x(x^2+1)^3
What is the first derivative of f(x)=(x^2+1)^4 ?
The first derivative of f(x)=(x^2+1)^4 is 8x(x^2+1)^3