What is the derivative of sqrt(3x-2) ?

The derivative of sqrt(3x-2) is 3/(2sqrt(3x-2))

What is the first derivative of sqrt(3x-2) ?

The first derivative of sqrt(3x-2) is 3/(2sqrt(3x-2))

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derivative of

3 x - 2

\frac{3}{2 3 x - 2}

Solution steps

\frac{d}{d x} (3 x - 2)

Apply the chain rule:

\frac{1}{2 3 x - 2} \frac{d}{d x} (3 x - 2)

= \frac{1}{2 3 x - 2} \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= \frac{1}{2 3 x - 2} \cdot 3

Simplify

\frac{1}{2 3 x - 2} \cdot 3 : \frac{3}{2 3 x - 2}

= \frac{3}{2 3 x - 2}

\int x^{6} e^{2 x} d x

\frac{3}{( x + 1 )}

\frac{d}{d x} (2 \cdot sin (2 x))

\frac{d}{d x} (a \cdot cos (x))

\int \frac{u}{2} d u

What is the derivative of sqrt(3x-2) ?
The derivative of sqrt(3x-2) is 3/(2sqrt(3x-2))
What is the first derivative of sqrt(3x-2) ?
The first derivative of sqrt(3x-2) is 3/(2sqrt(3x-2))